Yahoo Answers: Answers and Comments for A gaseous mixture contains 421.0 Torr H2(g), 376.1
Torr N2(g), and 84.7 Torr Ar(g). Calculate the mole fraction, χ, of each of these gases.? [Chemistry]
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Thu, 02 Apr 2020 00:47:57 +0000
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Yahoo Answers: Answers and Comments for A gaseous mixture contains 421.0 Torr H2(g), 376.1
Torr N2(g), and 84.7 Torr Ar(g). Calculate the mole fraction, χ, of each of these gases.? [Chemistry]
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From Roger the Mole: 421.0 Torr + 376.1 Torr + 84.7 Torr = 881.8 To...
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https://answers.yahoo.com/question/index?qid=20200402004757AAwOh0O
Thu, 02 Apr 2020 01:05:17 +0000
421.0 Torr + 376.1 Torr + 84.7 Torr = 881.8 Torr total
The number of moles of each gas is directly proportional to its partial pressure.
χH2 = (421.0 Torr) / (881.8 Torr) = 0.4774xN2 = (376.1 Torr) / (881.8 Torr) = 0.4265xAr = (84.7 Torr) / (881.8 Torr) = 0.09605