Yahoo Answers: Answers and Comments for I need help with a math problem please!!!? [Mathematics]
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enUS
Mon, 16 Dec 2019 05:22:21 +0000
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Yahoo Answers: Answers and Comments for I need help with a math problem please!!!? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20191216052221AAbGtbX
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From Ash: Surface area of Sphere, SA = πD² ....where D =...
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Mon, 16 Dec 2019 05:52:46 +0000
Surface area of Sphere, SA = πD² ....where D = diameter
Find derivative with time
d(SA)/dt = π(2 D) dD/dt
d(SA)/dt = 2πD dD/dt
dD/dt = (d(SA)/dt)/(2πD)
Given d(SA)/dt = 1 cm²/min .... (negative sign shows decrease in rate)
D = 10 cm
dD/dt = (1) /(2π*10)
dD/dt = 1/(20π)
dD/dt = 0.016 cm/min
The diameter of snowball decreases by 0.016 cm/min

From Anonymous: Area of a sphere = pi*diameter^2
Take the d...
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Mon, 16 Dec 2019 05:27:30 +0000
Area of a sphere = pi*diameter^2
Take the derivative
dA/dT = 2 * pi * d(diameter)dT
substituting
1 cm^2/sec = 2 * pi * d(diameter)dT
The rate at which the diameter decreases = 0.5 / pi cm^2/sec
I'm a little rusty on this so hopefully it help you to spot any mistakes I've done.

From John: whats your question?
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Mon, 16 Dec 2019 05:25:16 +0000
whats your question?