Yahoo Answers: Answers and Comments for A) What is the magnitude of the change in momentum of the 1000 kg of water? B) What is the direction of the change in momentum of water? ? [Physics]
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From Natalie
enUS
Sat, 16 Nov 2019 19:49:52 +0000
3
Yahoo Answers: Answers and Comments for A) What is the magnitude of the change in momentum of the 1000 kg of water? B) What is the direction of the change in momentum of water? ? [Physics]
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From RealPro: 1000*1.2sqrt(2) kgm/s at 135° counterclockwise...
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Sat, 16 Nov 2019 20:14:02 +0000
1000*1.2sqrt(2) kgm/s at 135° counterclockwise from the direction of entering velocity. You found this yourself too, right?

From Andrew Smith: Change in momentum = mass * change in velocity...
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Sat, 16 Nov 2019 20:57:27 +0000
Change in momentum = mass * change in velocity but velocity is a vector. So draw v2  v1 this has two parts One up and one to the left in a 45 degree right angled triangle. ie the change in velocity is 45 degrees up and to the left.
The magnitude is calculated by Pythagoras' theory. v= sqrt( v1^2 + v2^2) = 1.2 * sqrt( 2)
NOW change in momentum per second.
= mass per second * change in velocity
= 1000 * 1.2 * sqrt( 2) Up at 45 degrees to the left.
Note that the question is in error. You CAN calculate the change in momentum PER SECOND but the change in momentum continues to increase indefinitely. It does not HAVE a value.