Yahoo Answers: Answers and Comments for Solve the equation for the exact solutions over the interval [0,2pi) 8 tan 3x= 8? [Mathematics]
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From Damien
enUS
Tue, 22 Oct 2019 00:14:06 +0000
3
Yahoo Answers: Answers and Comments for Solve the equation for the exact solutions over the interval [0,2pi) 8 tan 3x= 8? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20191022001406AAPKNZp
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From Como: 
tan 3 x = 1
3x = π/4 , 5π/4 , 9π/4 , 13π...
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https://answers.yahoo.com/question/index?qid=20191022001406AAPKNZp
Tue, 22 Oct 2019 13:20:32 +0000

tan 3 x = 1
3x = π/4 , 5π/4 , 9π/4 , 13π/4 , 17π/4 , 21π/4
x = π/12 , 5π/12 , 3π/4 , 13π/12 , 17π/12 , 7π/4

From Wayne DeguMan: tan3x = 1
i.e. 3x = π/4 + nπ....for n = 0, 1,...
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https://answers.yahoo.com/question/index?qid=20191022001406AAPKNZp
Tue, 22 Oct 2019 09:39:50 +0000
tan3x = 1
i.e. 3x = π/4 + nπ....for n = 0, 1, 2,...
so, x = π/12 + nπ/3
=> x = π(1 + 4n)/12
Then, with n = 0, 1, 2,...we have:
x = π/12, 5π/12, 9π/12, 13π/12, 17π/12 and 21π/12...for [0, 2π)
:)>

From ted s: hint : tan Θ = 1 ===> Θ = π / 4 + nπ
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https://answers.yahoo.com/question/index?qid=20191022001406AAPKNZp
Tue, 22 Oct 2019 00:17:22 +0000
hint : tan Θ = 1 ===> Θ = π / 4 + nπ