Yahoo Answers: Answers and Comments for IP A gardener mows a lawn with an oldfashioned push mower. The handle of the mower makes an angle of 33 ∘ with the surface of the lawn.? [Physics]
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From derek
enUS
Wed, 18 Sep 2019 02:01:18 +0000
3
Yahoo Answers: Answers and Comments for IP A gardener mows a lawn with an oldfashioned push mower. The handle of the mower makes an angle of 33 ∘ with the surface of the lawn.? [Physics]
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From oubaas: Sin 33° = 0.545
Cos 33° = 0.839
motion equatio...
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Wed, 18 Sep 2019 02:48:19 +0000
Sin 33° = 0.545
Cos 33° = 0.839
motion equation
(m*g+F*sin 33)*μ = F*cos 33
(18*9.8+60*0.545)*μ = 60*0.839
209.1μ = 50.32
μ = 50.32/209.1 = 0.241
Fn = (18*9.8+60*0.545) = 209.1 N
if angle Θ (and therefore sin Θ) increases, then Fn increases ; if Θ increases such as sin Θ = 0.6, then Fn equates (18*9.8+60*0.6) = 212.4 N and μ' must be lower than μ.
212.4*μ' = 60*0.8
μ' = 48/212.4 = 0.226

From kuiperbelt2003: the normal force will be equal to the weight o...
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Wed, 18 Sep 2019 05:05:37 +0000
the normal force will be equal to the weight of the lawn mower plus the vertical component of the applied force. Find the weight by multiplying 18 kg x 9.8 m/s/s
The vertical component of the force is 60 sin 33.
If the angle increases, then the component of applied force in the vertical direction increases, and the normal force will also increase.