Yahoo Answers: Answers and Comments for I have V, and current for different lengths. I can get R with R=V/length. How does cross sectional area relate to the R vs. length graph? [Physics]
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From Anonymous
enUS
Wed, 11 Sep 2019 20:27:51 +0000
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Yahoo Answers: Answers and Comments for I have V, and current for different lengths. I can get R with R=V/length. How does cross sectional area relate to the R vs. length graph? [Physics]
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From NCS: It is not true that R=V/length.
You can get r...
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https://answers.yahoo.com/question/index?qid=20190911202751AA0Xjvn
Wed, 11 Sep 2019 21:04:57 +0000
It is not true that R=V/length.
You can get resistance R = V / I
where I ("eye") is the current (not l ("ell"), the length)
Furthermore, if you plot R vs length, you must hold the crosssectional area constant in order to get a meaningful graph.
It might be better to explain what your objective is. I suspect that it is to calculate the resistivity ρ of the wire material.
R = ρℓ / A
so, if you plot R (vertical) vs ℓ/A (horizontal) the slope of the line shoud be the resistivity of the conductor.
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From Andrew Smith: Although I could give you the answer there is ...
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Wed, 11 Sep 2019 20:58:24 +0000
Although I could give you the answer there is nothing in the question that gives any clues.
If this was an experiment you would be expected to take a number of pieces of wire of the same length but different diameters and discover the result.
If you take the theory you know that Resistance = resistivity ( a constant) * L/A
so that the gradient of the graph of R vs L is R/L = resistivity / A
ie the gradient of your graph is inversely proportional to the cross sectional area A