Yahoo Answers: Answers and Comments for I'm so confused with this math questioni'm terrible at math? [Mathematics]
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From Marissa
enUS
Fri, 14 Jun 2019 23:03:14 +0000
3
Yahoo Answers: Answers and Comments for I'm so confused with this math questioni'm terrible at math? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20190614230314AAEsawj
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From King Leo: .
Height of tall building
= 35 tan(21°) + 35 ...
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Fri, 14 Jun 2019 23:57:22 +0000
.
Height of tall building
= 35 tan(21°) + 35 tan(47°)
= 50.97 m
———— —

From Mike G: s = height of the shorter building
h = height ...
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Sat, 15 Jun 2019 01:00:36 +0000
s = height of the shorter building
h = height of the taller building above the shorter one
s/35 = tan47
s = 37.533 m
h/35 = tan21 = 13.4352
Height of taller building =
37.533+13.4352
= 50.968 m

From Jim Moor: First, draw a pic
use SOHCAHTOA since you hav...
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Fri, 14 Jun 2019 23:28:57 +0000
First, draw a pic
use SOHCAHTOA since you have right triangles.

From Starrysky: Draw it out on graph paper. Use trig function...
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Fri, 14 Jun 2019 23:11:07 +0000
Draw it out on graph paper. Use trig functions for angles measured from verticals and horizontals

From alex: Hint:
draw a diagram
use SOH , CAH or TOA
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Sat, 15 Jun 2019 02:40:04 +0000
Hint:
draw a diagram
use SOH , CAH or TOA

From BillM: That is a simple Right Triangle problem. Actua...
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Fri, 14 Jun 2019 23:16:18 +0000
That is a simple Right Triangle problem. Actually Two Right Triangles.
You solve the Triangle for the smaller one first then that will give you the numbers you need for the larger one.

From derfram: Draw out a picture. Remember that tan() = opp...
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Fri, 14 Jun 2019 23:12:46 +0000
Draw out a picture. Remember that tan() = opposite/adjacent
Tan(47°) = x/35
35 tan(47°) = x
x = 37.53 m << this is the height of the shorter building
tan(21°) = y/35
35 tan(21°) = y
y = 13.44 m << this is how much higher that tall building is over the shorter building
So height of taller building is x + y = 37.53 + 13.44 = 50.97 m
To use the right number of sig figs, height of taller building is 51 meters.

From JSG: What King Leo said.
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Mon, 17 Jun 2019 17:55:21 +0000
What King Leo said.

From L. E. Gant: Often, it's a matter of envisioning the pr...
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Fri, 14 Jun 2019 23:21:36 +0000
Often, it's a matter of envisioning the problem, especially this kind.
So, sketch the givens:
 draw the ground (horizontal line on the page)
 draw a vertical line for the short building (perpendicular to the ground line
 draw a vertical line for the taller building.
 draw a line perpendicular to the taller line to the "top" of the shorter building
 draw a line from the top of the shorter building to the top of the other one
 draw a line to the top of the shorter building to the bottom of the other
Now, put in the numbers that you know:
the ground between the buildings is 35 metres So two lines have this length.
the angle between the line across from the shorter building and the line to the top of the taller building is 21 degrees, and the line to the bottom of the taller building is 47 degrees.
Now use what you know of trigonometry, geometry and algebra.
Let h be the height of the taller building
and x be the height of the shorter building
so tan(21) = (hx)/35
==> hx = 35tan(21)
and tan(47) = x/35
==> x = 35tan(47)
you have two equations:
add them together
and you get:
h = 35tan(21) + 35tan(47) = 35 (tan(21) + tan(47))
look up tan(21) and tan(47) (or use your calculator)
and do the arithmetic
and you have the right answer

From nbsale: Lots of correct answers, but they seem to comp...
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Sat, 15 Jun 2019 00:55:26 +0000
Lots of correct answers, but they seem to complicate a very simple problem. Many fail to include a good picture, which should really be you starting point.
You solve it in two pieces, finding x and y as shown in the picture, then adding the values.
tan21 = x/35
x = 13.435
tan47 = y/35
y = 37.533
x+y = 50.968

From oldschool: Let R be a line from the top of the shorter to...
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Sat, 15 Jun 2019 00:09:49 +0000
Let R be a line from the top of the shorter to the base of the taller:
90°  47° = 43°
R = 35/sin43 = 51.32 = 35/cos47
Hs = R*sin47 = 51.32*sin47 = 37.53m height of the short building
Hd = 35*tan21 = 13.44m the amount taller
So the taller building is 37.53+13.44 = 50.97 or about 51m

From Captain Matticus, LandPiratesInc: Draw it out You have a triangle with an altit...
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Fri, 14 Jun 2019 23:47:54 +0000
Draw it out You have a triangle with an altitude of 35 meters. The side opposite of the observer can be broken into 2 segments, a and b. Using the law of sines, we can find their lengths
sin(47) / a = sin(90  47) / 35
sin(47) / a = cos(47) / 35
35 * sin(47) = a * cos(47)
35 * tan(47) = a
sin(21) / b = sin(90  21) / 35
35 * sin(21) = b * cos(21)
35 * tan(21) = b
35 * tan(47) + 35 * tan(21) =>
35 * (tan(47) + tan(21))
Make sure that your calculator is in degree mode
50.968146077103441512111665466154
To 2 sf
51 m