Yahoo Answers: Answers and Comments for Archimedes principle..Need help? [Physics]
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From crunner17
enUS
Tue, 04 Feb 2014 07:35:09 +0000
3
Yahoo Answers: Answers and Comments for Archimedes principle..Need help? [Physics]
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https://answers.yahoo.com/question/index?qid=20140204073509AAIbfOt
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From zella: Could you elaborate?
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Sun, 18 Sep 2016 04:57:35 +0000
Could you elaborate?

From AJAY: Please see link for answer
http://www.cisppu...
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https://answers.yahoo.com/question/index?qid=20140204073509AAIbfOt
Wed, 05 Feb 2014 05:14:46 +0000
Please see link for answer
http://www.cisppublishing.com/acatalog/info_109.html

From jimmymae2000: Impossible to fill a balloon to .5 atm,(in the...
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Tue, 04 Feb 2014 08:03:56 +0000
Impossible to fill a balloon to .5 atm,(in the atmosphere).

From Lucas C: Archimedes Principle says that if the setup j...
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Tue, 04 Feb 2014 08:02:13 +0000
Archimedes Principle says that if the setup just floats, then its weight must be equal to the weight of the displaced air. First let's calculate the mass and volume of each fullyinflated balloon.
The empty mass of the balloon is 0.01 kg, and it contains 0.061 kg of helium (I assume you meant kg and not moles). That gives each balloon a total mass of 0.071 kg. Now let's work out the volume.
The molar mass of helium is 4.0026 g/mol, or 0.0040026 kg/mol. So a balloon with 0.061 kg contains 15.2 moles of helium:
0.061 kg He x (1 mol He / 0.0040026 kg He) = 15.2 mol
If the gauge pressure is 0.50 atm, then the total pressure inside the balloon must be 1.50 atm (since the ambient pressure is standard, or 1 atm). And the temperature inside the balloon is 273 K. We have enough information to calculate the volume of the balloon:
PV = nRT
V = nRT / P = (15.2 mol)(0.0821 L*atm/mol*K)(273 K) / (1.50 atm)
V = 227 L
So each balloon displaces 227 L of air. Let's calculate the mass of 227 L of air (in this case, pure N2, molar mass = 28.013 g/mol) at STP
PV = nRT
n = PV / RT = (1 atm)(227 L) / (0.0821 L*atm/mol*K)(273 K)
n = 10.1 mol
10.1 mol N2 x (28.013 g N2 / 1 mol N2) = 284 g N2 = 0.284 kg
So each 0.071 kg balloon displaces 0.284 kg of air, a difference of 0.213 kg. The buoyant force on each balloon is therefore equal to the weight of 0.213 kg. If you want to lift a 12 kg mass (with apparently negligible volume), then you need:
N = 12 kg / 0.213 kg = 56.4 balloons
Of course you can't have 0.4 balloon, so let's say 56 balloons and a 57th balloon that's a little underinflated.
I hope that helps. Good luck!