Yahoo Answers: Answers and Comments for Help solving math problem? [Mathematics]
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From Mike
enUS
Wed, 17 Apr 2013 14:21:13 +0000
3
Yahoo Answers: Answers and Comments for Help solving math problem? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20130417142113AAdaTxA
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From salado: 2x + 2y = 20 utilising the simultaneous techni...
https://answers.yahoo.com/question/index?qid=20130417142113AAdaTxA
https://answers.yahoo.com/question/index?qid=20130417142113AAdaTxA
Thu, 01 Dec 2016 03:31:42 +0000
2x + 2y = 20 utilising the simultaneous technique 2x  2y = 4 ____________ 4x = 24 ( divide by potential of four) x = 6 replace x in considered one of the two equations 2x + 2y = 20 2 (6) + 2y = 20 12 +2y = 20 2y = 20  12 2y = 8 (divide by potential of two) y = 4 answer : X = 6 , Y = 4

From Bagel: Let c = number of covered seats sold, u = numb...
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https://answers.yahoo.com/question/index?qid=20130417142113AAdaTxA
Wed, 17 Apr 2013 14:27:04 +0000
Let c = number of covered seats sold, u = number of uncovered seats sold.
First write the cost equation.
50c + 20u = 23500
This shows that $50 per covered seat sold, plus $20 per uncovered seat sold, totals $23500.
Now write the sales equation.
c + u = 725
This shows that the total number of covered and uncovered seats sold totals 725. Rewrite the equation with one variable by itself.
c = 725  u
Now substitute (725u) for c in the cost equation.
50(725u) + 20u = 23500
36250  50u + 20u = 23500
36250  30u = 23500
30u = 12750
u = 425
There were 425 uncovered seats sold. Now substitute 425 for u in the sales equation.
c = 725  425
c = 300
There were 300 covered seats sold.