Yahoo Answers: Answers and Comments for 6(4 +2x) = 4(2x1) + 4(x + 3)? [Mathematics]
Copyright © Yahoo! Inc. All rights reserved.
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
From Beth
enUS
Sun, 01 Jul 2012 12:28:41 +0000
3
Yahoo Answers: Answers and Comments for 6(4 +2x) = 4(2x1) + 4(x + 3)? [Mathematics]
292
38
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://s.yimg.com/zz/combo?images/emaillogous.png

From Bubbles: 6(4 +2x) = 4(2x1) + 4(x + 3) <= original e...
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
Sun, 01 Jul 2012 19:35:57 +0000
6(4 +2x) = 4(2x1) + 4(x + 3) <= original equation
24 + 12x = 8x  4 + 4x + 12 <= simplify by distribution
24 + 12x = 12x + 8 <= combine like terms on right side of equation (the x's  just add them together)
24 ≠ 8 <= subtract 12x from both sides; 24 does not equal 8
Now, when the result is two numbers that clearly do not equal each other, this is considered "no solution," or no valid solution for x. If, for example, you were left with 8 = 8, this is considered to be "all real numbers," meaning x can equal all real numbers, so x has an infinite numbers of answers!
Hope this helps! :)

From JOS J: 6(4 +2x) = 4(2x1) + 4(x + 3)
24 + 12 x =...
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
Sun, 01 Jul 2012 19:33:05 +0000
6(4 +2x) = 4(2x1) + 4(x + 3)
24 + 12 x = 8 + 12 x
No Solution

From Keith Roberts: Hi there 
Two things to keep in mind in t...
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
Sun, 01 Jul 2012 20:03:39 +0000
Hi there 
Two things to keep in mind in this problem. Making sure that you properly distribute your quantities, and knowing what to do when you end up with a "solution" that is a contradiction  which we end up getting in this problem. Whenever we reduce an equation to a contradiction (i.e. 4 = 12, 2 = 1, 0 = 1, etc.) it means there is no solution to the equation. Here's how we end up with one:
6(4 + 2x) = 4(2x  1) + 4(x + 3)
6∙4 + 6∙2x = 4∙2x  4∙1 + 4∙x + 4∙3
24 + 12x = 8x  4 + 4x + 12
24 + 12x = 12x + 8
24 + 12x  24 = 12x + 8  24
12x = 12x  16
12x  12x = 12x  12x  16
0 = 16
which is the contradiction. Which means this equation has no solutions.
I put together a short video tutorial walkthrough of a solution to your question, and listed it below as well. Hope it's helpful!

From Sun: 6(4+2x)=4(2x1)+4(x+3),
24+12x=8x4+4x+12,
...
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
Sun, 01 Jul 2012 19:32:31 +0000
6(4+2x)=4(2x1)+4(x+3),
24+12x=8x4+4x+12,
24+12x=12x4+12,
24+12x=12x+8,
24=12x12x+8,
24=8, no solution.
Answer: No Solution.

From Sepia: 6(4 + 2x) = 4(2x  1) + 4(x + 3)
24 + 12x = 8...
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
Sun, 01 Jul 2012 19:57:21 +0000
6(4 + 2x) = 4(2x  1) + 4(x + 3)
24 + 12x = 8x  4 + 4x + 12
12x  8x  4x = 4 + 12  24
0 = 16
False.

From Sweet Satisfaction: I got 0.8 though I could be wrong.
Use the ...
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
https://answers.yahoo.com/question/index?qid=20120701122840AABzJZY
Sun, 01 Jul 2012 19:46:27 +0000
I got 0.8 though I could be wrong.
Use the five finger steps:
1.) Get rid of paranthesis <distribute>
2.) Combine like terms
3.) Get variable on one side
4.) Get constant on other side (+ or )
5.) Divide by coefficient (* or ÷)
P.S. When solving equations like these, it would be opposite.