Yahoo Answers: Answers and Comments for Percent and probability? [Mathematics]
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From Tammy
enUS
Sat, 16 Jun 2012 04:31:54 +0000
3
Yahoo Answers: Answers and Comments for Percent and probability? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20120616043154AAnF1qg
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From James: x = 5.88
mean = 5.93
SD = 0.59
z score = ?
...
https://answers.yahoo.com/question/index?qid=20120616043154AAnF1qg
https://answers.yahoo.com/question/index?qid=20120616043154AAnF1qg
Sat, 16 Jun 2012 05:35:34 +0000
x = 5.88
mean = 5.93
SD = 0.59
z score = ?
Find your z score.
(5.88  5.93) / 0.59 =  0.085
P(z = 0.085) = 0.4661
P(x < 5.88) = 0.4661
P(x > 5.88) = 1  0.4661 = 0.5339
Therefore, greater than 5.88 is 53.39%

From Anonymous: Here, mean = 5.93 and standard deviation = 0.5...
https://answers.yahoo.com/question/index?qid=20120616043154AAnF1qg
https://answers.yahoo.com/question/index?qid=20120616043154AAnF1qg
Sat, 16 Jun 2012 05:17:55 +0000
Here, mean = 5.93 and standard deviation = 0.59
Z_value of the score 5.88 is
= (5.88 – 5.93)/0.59
= 0.085
So the probability of grapefruits in an orchard larger than 5.88 is
= P (x > 5.88)
= P (z > 0.085)
= 0.533869305
= 53.39 %
From TutorTeddy.com

From None: (5.93  5.88)/0.59 = 0.0847, the number of SD&...
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https://answers.yahoo.com/question/index?qid=20120616043154AAnF1qg
Sat, 16 Jun 2012 05:11:20 +0000
(5.93  5.88)/0.59 = 0.0847, the number of SD's below the mean. From a table of the standard normal distribution, you can see that the probability of a value greater than 5.88 is 0.5338 so 53.38% of the grapefruit will be larger than 5.88 inches.
[P(Z = 0.0847) =0.5338. Because the normal distribution is symmetrical, the cumulative probability from  infinity to Z = 0.0847 is the same as the cumulative probability from Z = 0.0847 to infinity.
http://www.math.unb.ca/~knight/utility/NormTble.htm
0.5339 because the sample is not the population. However, in either case, calculations carried out to 4 places are of questionable value because the data are only good to 3 places. Accordingly, one would say that the % of them that are larger than 5.88 in is 53.4% and the probability that the mean of a sample of 100 exceeds 5.88 in is 0.534