Yahoo Answers: Answers and Comments for What is the probability of getting exactly one ace in a 5 card poker hand? [Mathematics]
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From Summer
enUS
Wed, 18 Apr 2012 05:35:35 +0000
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Yahoo Answers: Answers and Comments for What is the probability of getting exactly one ace in a 5 card poker hand? [Mathematics]
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From Andy J: There are 53C5 = 2598960 possible 5card hands...
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Wed, 18 Apr 2012 05:46:08 +0000
There are 53C5 = 2598960 possible 5card hands.
There are 4 aces and 48 nonaces. There are 4 ways to choose one ace, and 48C4 = 194580 ways to choose 4 more cards to fill out the hand from the nonaces. Total number of hands is 4 * 194580 = 778320.
Probability is 778320 / 2598960 = 3243 / 10829 or about 0.2995.
EDIT: x8oi, the question explicitly asks about *exactly* one ace, not *at least* one ace as you have calculated.
EDIT 2: gjdolby, your answer would be correct if we cared about the order the cards were drawn. We don't, so we need to multiply your answer by the number of positions the ace could be drawn in, which is 5C1 = 5:
0.059894727 * 5 = 0.299473635 agreeing with my answer.

From x8oi: There are 52 nonjoker cards in a pack.
There...
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Wed, 18 Apr 2012 05:41:28 +0000
There are 52 nonjoker cards in a pack.
There are 4 aces in a pack.
The probability of having 1 ace if dealt 1 card is 4/52 (~7.692%).
For your second card (assuming the first card wasn't an ace), the probability is 4/51 (~7.842%)
For your third card (assuming the first and second cards weren't an ace), the probability is 4/50 (8%)
(etc)
But... to work out the combined probabilities, you have to work out the probability that you *won't* be dealt an ace. Then you multiply them together. So:
(48/52) * (47/51) * (46/50) * (45/49) * (44/48) = ~ 65.88%
So the probability that you *will* be dealt an ace is 100%  65.88%.
Thus, the probability that at least one card in your hand is an ace is about 34%.
EDIT: Andy J is right. I accept defeat. :(

From dotto: Poker Hand Probability
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Wed, 09 Nov 2016 07:13:47 +0000
Poker Hand Probability

From Saul: The chance of one ace being drawn is 4/52 on t...
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Mon, 22 Feb 2016 01:45:18 +0000
The chance of one ace being drawn is 4/52 on the first draw. If non drawn the next card is 4/51, then next 450 and 4/49 and 4/48.each time an ace is drawn the3 top number will reduce by one. So if the first card is an ace the next odds would be 3/51 and so on. To draw 2 aces in 5 cards is (5 x 2/4)/52 = 2.1/2 in 52. or just under 5%.

From Φ² = Φ+1: 1 card is one of four aces, and the other 4 ca...
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Wed, 18 Apr 2012 05:55:14 +0000
1 card is one of four aces, and the other 4 cards are drawn from the remaining 48 nonaces.
4/52 * 48/51 * 47/50 * 46/49 * 45/48 = 6486 / 108290 ≈ 0.059894727