Yahoo Answers: Answers and Comments for Physics problem please help. (The avogadro number)? [Physics]
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From Unbreakable Dude
enUS
Wed, 15 Feb 2012 09:19:52 +0000
3
Yahoo Answers: Answers and Comments for Physics problem please help. (The avogadro number)? [Physics]
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https://answers.yahoo.com/question/index?qid=20120215091952AAXEUd5
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From Anonymous: Hey Dude,
So, if the number of electrons th...
https://answers.yahoo.com/question/index?qid=20120215091952AAXEUd5
https://answers.yahoo.com/question/index?qid=20120215091952AAXEUd5
Wed, 15 Feb 2012 09:28:00 +0000
Hey Dude,
So, if the number of electrons that were rubbed off is avogadro's number as you say, all you do next is multiply the charge of an electron, 1.602*10^19 C. Your answer is 96,440 coulombs. Hope this helps.
Best,
David

From Donna: K is the Boltzmann Constant, which is the univ...
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Mon, 16 May 2016 14:10:05 +0000
K is the Boltzmann Constant, which is the universal gas constant R = 8.314 divided by Avagadro's number. Therefore k has a value of 1.380*10^23 J K ^1 Ek would then be 1.5* 1.380*10^23* 435 J = 9.00 * 10^21J per molecule. For 1 mol, multiply by Avagadro's number. But this is just going around in circles because above we divided by Avagadro's number to get the Boltzmann constant. It is there fore much simpler to say that the kinetic energy of 1 mol ideal gas is given by the equation: Ek = 3/2 RT where R is the universal gas constant and T is temperature in K . For 1.31 mol multiply again by 1.31. I leave it to you to do the arithmetic.