Yahoo Answers: Answers and Comments for How to find margin of error & confidence interval on TI83 in this problem? [Homework Help]
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From curious
enUS
Sun, 06 Nov 2011 09:20:04 +0000
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Yahoo Answers: Answers and Comments for How to find margin of error & confidence interval on TI83 in this problem? [Homework Help]
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From kinjorski: Margin Of Error Calculator
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Thu, 29 Sep 2016 03:52:15 +0000
Margin Of Error Calculator

From JoAnn: For the best answers, search on this site http...
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Wed, 06 Apr 2016 14:33:53 +0000
For the best answers, search on this site https://shorturl.im/awLDG
c) The way my stats teacher taught us to calculate the margin of error was: ME = z* x SE(x) I found the z* using invNorm(.025) on my calculator (a TI83), however you might do it some other way. Then SE, or standard error, is your standard deviation divided by the square root of your sample size. So, 16.16 / √5 = 7.2250. Substitute these values and you have your answer. ME = z* x SE(x) ME = 1.96 x 7.2250 ME = 14.1609 However, if you have learned about the t model, it would be smarter to use this since your sample size of 5 is so small. If not, ignore this part. In this case, you would have to find t* which is invT on a calculator, or you can use a table to get the value of 2.776. It would be solved almost exactly the same after this. ME = z* x SE(x) ME = 2.776 x 7.2250 ME = 20.0565 d) A confidence interval is found using the following equation: x ± (ME) where x is 75. If you used the z*, you would get a value of 60.8391 to 89.1609. If you used the t*, you would get a value of 54.9435 to 95.0565. Hope this helps!

From nursegoodbodyandmind: I had the same question and just found the ans...
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Mon, 07 Nov 2011 08:13:34 +0000
I had the same question and just found the answer, so I thought I'd share.
Do the 2PropZInt (scroll down below 2PropZTest). Then, you take the upper confidence level limit and subtract the lower confidence level limit. Then, divide by 2.
http://users.rowan.edu/~schultzl/TI/1PropZInterval.pdf