Yahoo Answers: Answers and Comments for Physics problem latent heat. Help? [Physics]
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From Dav479
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Fri, 27 May 2011 19:18:07 +0000
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Yahoo Answers: Answers and Comments for Physics problem latent heat. Help? [Physics]
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https://answers.yahoo.com/question/index?qid=20110527191806AAr4tIf
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From schuller: you're able to desire to evaluate it in 3 ...
https://answers.yahoo.com/question/index?qid=20110527191806AAr4tIf
https://answers.yahoo.com/question/index?qid=20110527191806AAr4tIf
Thu, 13 Oct 2016 09:39:28 +0000
you're able to desire to evaluate it in 3 steps. a million) the warmth necessary to heat the ice from 10 C to 0 C. 2) the warmth necessary to soften the ice. 3) the warmth necessary to heat the water from 0 C to ninety C. To do steps a million and 3 you will pick the specific warmth skill of ice and liquid water respectively.

From *Mastermind*: Specific heat capacity, ice: 2108 J/kgC`
Spe...
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https://answers.yahoo.com/question/index?qid=20110527191806AAr4tIf
Fri, 27 May 2011 20:49:17 +0000
Specific heat capacity, ice: 2108 J/kgC`
Specific heat capacity, water: 4187 J/kgC`
latent heat of fusion for ice is 3.35*10^5 J/kg
Energy required for the temperature rise form 8 degree celsius to 0 degree celsius is;
E=mc(<>T)
=0.80 x 2108 x 8
=13491.20J
E=mc(<>T) where E=energy, m=mass, c=Specific heat capacity of ice, <>T= change in temperature

Energy required for the icetowater conversion is;
E=mL
=0.80 x 3.35*10^5
=268000J
E=mL where E=energy, m=mass, L= latent heat of fusion of ice

Energy required for the temperature rise form 0 degree celsius to 37 degree celsius is;
E=mc(<>T)
=0.80 x 4187 x 37
=123935.20J
E=mc(<>T) where E=energy, m=mass, c=Specific heat capacity of water, <>T= change in temperature

Therefore, now add up all the energy(s) to calculate the total energy required for the whole process;
Total energy = 13491.20 + 268000 + 123935.20
= 405426.40J
= 405.43 KJ
Therefor the energy absorbed from your body if you eat 0.80kg of 8 degree celsius snow which your body warms to body temperature of 37 degree celsius is 405.43 KJ
N.B Use the values of Specific heat capacity of water, ice and specific latent heat of fusion of ice give in your book/question.