Yahoo Answers: Answers and Comments for Why does magnetic force equal centripetal force? [Physics]
Copyright © Yahoo! Inc. All rights reserved.
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
From alliebabii
enUS
Tue, 05 Apr 2011 16:17:15 +0000
3
Yahoo Answers: Answers and Comments for Why does magnetic force equal centripetal force? [Physics]
292
38
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
https://s.yimg.com/zz/combo?images/emaillogous.png

From morningstar: If a charged particle is moving perpendicular ...
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
Tue, 05 Apr 2011 17:43:57 +0000
If a charged particle is moving perpendicular to a magnetic field, it will start curving. It will go around a circle and come back to where it started. The radius of that circle will be r.
You can change the magnetic force by changing B or v or maybe even q. You might think, then it will no longer be equal to mv^2/r. But r will change so that mv^2/r changes to match Bqv.
Imagine you increase the magnetic field. Then the charged particle will make a tighter turn. If you decrease it, it makes a wider turn. Either way, it keeps turning the same direction, and eventually comes back to where it started.
If it moves in a circle at a constant speed, then Bqv = mv^2/r must be true for some value of r.
Why does it move in a circle at a constant speed? The assumptions are that there are no other forces on the particle and that the B field is uniform. The magnetic force is always perpendicular to the direction of motion. A perpendicular force can do no work, so it can't add or remove kinetic energy. That explains the constant speed. When something moves in a circle, the direction of motion, which is tangent to the circle, is perpendicular to the acceleration, which points to the center along the radius of the circle. That explains why a circle is a path that can result from a perpendicular force.

From breault: If mass greater, centripetal tension will adva...
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
Sat, 19 Nov 2016 03:45:46 +0000
If mass greater, centripetal tension will advance because of the fact F=ma. If radius greater, centripetal tension decreases because of the fact centripetal acceleration, a.ok.a. radial acceleration is a=v^2/r. Plug that into F=ma, and you get F=(mv^2)/r. If tangential velocity greater, centripetal tension might advance.

From L.E.: Because both forces cause centripetal accelera...
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
https://answers.yahoo.com/question/index?qid=20110405161715AAuefVm
Tue, 05 Apr 2011 16:22:28 +0000
Because both forces cause centripetal acceleration (circular motion).
In this case, the magnetic force is A TYPE OF centripetal force (as opposed to linear force).
Hope this helps.