Yahoo Answers: Answers and Comments for Through a sphere, a cylindrical hole of radius 3ft is drilled. What is the volume of the part remaining? [Mathematics]
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From Bail Out
enUS
Mon, 14 Feb 2011 17:35:17 +0000
3
Yahoo Answers: Answers and Comments for Through a sphere, a cylindrical hole of radius 3ft is drilled. What is the volume of the part remaining? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20110214173517AAA6kPv
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From Anonymous: not enough information
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Mon, 14 Feb 2011 17:42:19 +0000
not enough information

From dontas: volume of the remainder sphere (holed one) is ...
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Mon, 12 Dec 2016 01:18:34 +0000
volume of the remainder sphere (holed one) is given via (4/3)(22/7)R^3  volume bumped off = (4/3)(22/7)R^3  [ volume of a cylinder of radius 2 and height 2 sqrt(R^2  2^2) + volume of two segments of sphere subtending attitude 2 arcsin(2/R) on the centre] = (4/3)(22/7)R^3  [ (22/7)*2^3 sqrt(R^2  4) + 2{ (pi/6) (3*2^2 + h^2)h}] the place h = R  sqrt(r^2  2^2)

From Anonymous: 4/3 pi r^3  pi r^2 h
Subtract the volume ...
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Tue, 15 Feb 2011 05:24:30 +0000
4/3 pi r^3  pi r^2 h
Subtract the volume of cylinder from vol. of sphere..you didnt provide all information like height of cylinder, radius of sphere!

From mohammad B: you need the radius of sphere
the remaining v...
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Tue, 15 Feb 2011 00:26:19 +0000
you need the radius of sphere
the remaining volume is
V=22/7(4/3R^318(R^29)^1/2)
THIS WILL GIVE THE APPROXIMATE VOLUME.