Yahoo Answers: Answers and Comments for Imaginary numbers. put into standard form? [Mathematics]
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From Jiggy Jon
enUS
Wed, 28 Jan 2009 12:20:46 +0000
3
Yahoo Answers: Answers and Comments for Imaginary numbers. put into standard form? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
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From ?: The 'standard form' for an imaginary n...
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
Thu, 26 May 2016 08:54:22 +0000
The 'standard form' for an imaginary number is i*b where i is the imaginary unit (sqrt(1) and b is the magnitude of the imaginary value expressed as a 'normal' (or real) value. The i is usually written first to 'alert' the reader that what follows is an imaginary value. Also, in electrical engineering, the j is usually used for the imaginary unit since a lower case i is used for instantaneous current. Remember that sqrt(a*b) = sqrt(a) * sqrt(b) so....... In your problem, factor out the 1 from each of the radicals and write the imaginary value as i*(2*sqrt(49) + 3*sqrt(64)) and simplify it to i*(2*7 + 3*8) = i*38 Doug

From Ashley.: 12+30i+14i+35i^2
12+44i+35i^2
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
Wed, 28 Jan 2009 12:29:30 +0000
12+30i+14i+35i^2
12+44i+35i^2

From you: 12 +16i 35i2
= 17 +16i
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
Wed, 28 Jan 2009 12:28:57 +0000
12 +16i 35i2
= 17 +16i

From Anonymous: erm how about you do it yourself
that's...
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
https://answers.yahoo.com/question/index?qid=20090128122046AA6ES7Y
Wed, 28 Jan 2009 12:28:55 +0000
erm how about you do it yourself
that's what other people do