Yahoo Answers: Answers and Comments for I need help with boyle's law calculations.? [Homework Help]
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Wed, 14 Jan 2009 17:37:31 +0000
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Yahoo Answers: Answers and Comments for I need help with boyle's law calculations.? [Homework Help]
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From Anonymous: Its asking you exactly what the equation means...
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Thu, 15 Jan 2009 01:51:09 +0000
Its asking you exactly what the equation means. You start out with 425cm2 of oxygen at a pressure of 9.80 kPa. And you want to figure out what the new volume will be when the pressure becomes 9.40kPa. So you plug it in like
P1V1=P2V2
9.80kPa(425cm2)=9.40kPaV2.
It's easiest to isolate the variable you're trying to figure for (V2) by dividing both sides by P2.
So next you would write
V2=(9.80kPa[425cm2])/9.40kPa
Just multiply P1 and V1, then divide your answer by P2.
When gas molecules are exposed to different pressures, their volume changes accordingly. Just like if they're put into a larger container and the volume increases, the pressure will decrease. If you have 3 of the variables, you can solve for the fourth just like any other mathematical equation.

From Anonymous: For this problem, and other Boyle's Law ca...
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Thu, 15 Jan 2009 01:49:27 +0000
For this problem, and other Boyle's Law calculations, you will need to rearrange your given equation P1V1=P2V2 to solve for the unknown. In your case, you would like to find V2, which represents the volume after a change in pressure.
So...
Let V1 = initial volume = 425 cm^3
Let P1 = initial pressure = 9.80 kPa
Let P2 = final pressure = 9.40 kPa
V2 = ???
Rearrange the equation P1V1=P2V2 to solve for V2. To do this, divide both sides by P2, resulting in the following equation:
P1V1/P2 = V2
(initial volume times initial pressure divided by final pressure equals the final volume)
Plug in your knowns (P1,V1,P2) and solve for V2.
Your final answer should be 443 cm^3

From Dr. Merlin Bach: P1V1=P2V2
(9.80 kPa)(425 cm^3)= (9.40 kPa)(...
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Thu, 15 Jan 2009 01:44:15 +0000
P1V1=P2V2
(9.80 kPa)(425 cm^3)= (9.40 kPa)(x)
4165=9.40x
x=443 cm^3