Yahoo Answers: Answers and Comments for Power=i square X r=v square/r explain the double proportion of resistence to power? [Physics]
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From oo7
enUS
Thu, 17 Apr 2008 08:38:29 +0000
3
Yahoo Answers: Answers and Comments for Power=i square X r=v square/r explain the double proportion of resistence to power? [Physics]
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From ?: I Squared R
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Sat, 05 Nov 2016 05:04:16 +0000
I Squared R

From Anonymous: As you already know,
power = voltage x cur...
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Thu, 17 Apr 2008 08:59:29 +0000
As you already know,
power = voltage x current
resistance = voltage / current
If you want to express power only in terms of voltage and resistance, you must take the first equation and substitute for current, using the second equation. When you do that, you get (here comes the algebra):
power = voltage x (voltage / resistance) or,
power = voltage^2 / resistance.
The same substitution concept works whan you express power in terms of just current and resistance.

From Bwts: P=I^2xR=V^2/R
real power is dissipated as h...
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Thu, 17 Apr 2008 08:54:45 +0000
P=I^2xR=V^2/R
real power is dissipated as heat due to the resistive element impeding the flow of electrons
so if you increase the current (rate of flow of electrons) through a device then you have more electron collisions and hence more heat

From Jim Phillips: WTF!!1
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Thu, 17 Apr 2008 08:40:56 +0000
WTF!!1