Yahoo Answers: Answers and Comments for How to you find degrees of freedom (ztable)? [Homework Help]
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From JJ
enUS
Sun, 13 Apr 2008 12:23:31 +0000
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Yahoo Answers: Answers and Comments for How to you find degrees of freedom (ztable)? [Homework Help]
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From Anonymous: This Site Might Help You.
RE:
how to you find...
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Wed, 19 Aug 2015 00:24:10 +0000
This Site Might Help You.
RE:
how to you find degrees of freedom (ztable)?
this is my problem for stats:
a disk manufacturer wishes to know the fraction of disks his companies makes which are defective.
suppose a sample of 1527 floppy disks is drawn and of those 122 were defective. Construct an 85% confidence interval for the population proportion of disks which...

From Bong: P value is a statistical measure that helps sc...
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Sun, 29 Mar 2015 22:54:43 +0000
P value is a statistical measure that helps scientists determine whether or not their hypotheses are correct. P values are used to determine whether the results of their experiment are within the normal range of values for the events being observed. Usually, if the P value of a data set is below a certain predetermined amount (like, for instance, 0.05), scientists will reject the "null hypothesis" of their experiment  in other words, they'll rule out the hypothesis that the variables of their experiment had no meaningful effect on the results. Today, p values are usually found on a reference table by first calculating a chi square value

From rman: finding the degrees of freedom is a very easy ...
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Sun, 13 Apr 2008 12:59:56 +0000
finding the degrees of freedom is a very easy thing. it is usually N1. That is the total sample population minus 1. However in this case the degrees of freedom are not necessary. U are making a confidence interval right? This problem is whats known as a 1 proportion z test. If u have a TI 83 graphing calculator this problem is very easy. You go to STAT then TESTS and then scroll down until you find 1 prop z int. You plug in the info and it will calculate for u. If you do not have one the problem is a bit more work. first u will need to find the z test staistic for the 85 percent confidence level. DO this by looking up 85 percent on table. Looking it up on my table i see that it is between .8485 and .8508. This correpsonds to the z test statistic 1.13 and 1.14. Find the avg between these two numbers which is 1.135. This is ur z test statistic. The confidence interval is found by:
the statistic( 122/1527) plus/minus 1.135 times the standard deviation. the standard deviation for a proportion is found by the square root of (the statistic X (1statistic) divided by the total sample size(1527)).
Hope this helps.