Yahoo Answers: Answers and Comments for Question below? [Mathematics]
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From Anonymous
enUS
Fri, 22 Dec 2006 01:42:37 +0000
3
Yahoo Answers: Answers and Comments for Question below? [Mathematics]
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https://answers.yahoo.com/question/index?qid=20061222014237AA5ruAZ
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From locuaz: you need to multiply kA by (k^1A^1)
kA(k^...
https://answers.yahoo.com/question/index?qid=20061222014237AA5ruAZ
https://answers.yahoo.com/question/index?qid=20061222014237AA5ruAZ
Fri, 22 Dec 2006 22:36:11 +0000
you need to multiply kA by (k^1A^1)
kA(k^1A^1)=(kk^{1}) AA^{1} = 1 I = I
so (k^1A^1) has to be the inverse of kA,
i.e. (kA)^{1} = (k^1A^1) .

From lola l: multiply kA by (k^1A^1), if you get the iden...
https://answers.yahoo.com/question/index?qid=20061222014237AA5ruAZ
https://answers.yahoo.com/question/index?qid=20061222014237AA5ruAZ
Sat, 23 Dec 2006 15:55:38 +0000
multiply kA by (k^1A^1), if you get the identity it means that (k^1A^1) is the inverse of kA:
kA(k^1A^1)=(kk^{1}) AA^{1} = 1 I = I