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# CHEMISTRYYY! PLEASE HELP?

Octane (C8H18) is the main component of gasoline and has a density of 2661.14 grams/gallon. How many grams of CO2 are produced from the combustion of 0.750 gallons of octane?

2C8H18 + 25O2 16CO2 + 18H2O

### 2 Answers

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• 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

(0.750 gallons C8H18) x (2661.14 grams/gallon) / (114.2285 g C8H18/mol) x

(16 mol CO2 / 2 mol C8H18) x (44.00964 g CO2/mol) = 6152 g CO2

• 2661.14 grams/gallon x 0.750 gallons  = 1995 g

Octane + Oxygen ➜ Carbon Dioxide + water2C₈H₁₈ + 25O₂ ➜ 16CO₂ + 18H₂Omolecular weightsC = 12H = 1O = 162C₈H₁₈ = 2(8•12+18) = 22825O₂ = 25•16•2 = 80016CO₂ = 16(12+32) = 70418H₂O = 18•18 = 324check 228+800 = 704+324 = 1028 ok2 mole of C₈H₁₈ + 25 moles of O₂ ➜ 16 mole of CO₂ + 18 moles of H₂O

228 grams of C₈H₁₈ + 800 grams of O₂ ➜ 704 grams of CO₂ + 324 grams of H₂O

gram ratio of CO₂ to C₈H₁₈ is 704/228

704/228 = x/1995

x = 6160 g

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