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find the current?
I tried 3 times to solve it, each time a different answer.
please can you find the Ammeter reading?
- oldschoolLv 71 month agoFavorite Answer
The easiest way is node analysis. Let the left side be node Vx and the right side assume is ground. There are 4 "branches", 4 currents assumed leaving Vx. By KCL, their sum = 0:
Vx/8.2 + (Vx-6.8)/10 + (Vx-4.5)/5 + Vx/8.2 = 0 Multiply eq. by 820
100Vx + 82Vx - 557.6 +164Vx - 738 + 100Vx = 0
100Vx + 82Vx + 164Vx + 100Vx = 557.6 + 738
100Vx + 82Vx + 164Vx + 100Vx = 1295.6
446Vx = 1295.6
Vx = 1295.6/446 = 3239/1115 or about 2.9V
i = 2.9/8.2 = 158/446 = 79/223 or about 0.354A = 354mA
- PhilomelLv 71 month ago
a. 389.5mA >
a. 49.3mA <