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# find the current?

I tried 3 times to solve it, each time a different answer.

please can you find the Ammeter reading? ### 2 Answers

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• Favorite Answer

The easiest way is node analysis. Let the left side be node Vx and the right side assume is ground. There are 4 "branches", 4 currents assumed leaving Vx. By KCL, their sum = 0:

Vx/8.2 + (Vx-6.8)/10 + (Vx-4.5)/5 + Vx/8.2 = 0   Multiply eq. by 820

100Vx + 82Vx - 557.6 +164Vx - 738 + 100Vx = 0

100Vx + 82Vx + 164Vx  + 100Vx = 557.6 + 738

100Vx + 82Vx + 164Vx + 100Vx = 1295.6

446Vx = 1295.6

Vx = 1295.6/446 = 3239/1115 or about 2.9V

i = 2.9/8.2 = 158/446 = 79/223 or about 0.354A = 354mA

• a.  389.5mA  >

b. 2.3V

C.

a.   49.3mA   <

b.    11.3V

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