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Anonymous asked in Science & MathematicsPhysics · 2 months ago

The impedance of the parallel RLC circuit?

The impedance of the parallel RLC circuit shown is given by:

(The answer is B)Thanks

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2 Answers

  • ?
    Lv 7
    2 months ago
    Favorite Answer

    Consider the capacitor and the inductor.  The impedance of the capacitor is 1/wC.  The impedance of the inductor is in the reverse direction and is therefore -wL To add things in parallel we add their conductivities so the conductivity is wC - 1/wL

    The conductivity of the resistor is 1/R  but is 90 degrees different so that to get the resultant conductivity we must add using pythagoras' theory

    conductivity = sqrt( 1/R^2 +(wC-1/wL)^2)

    finally the magnitude of the impedance is the inverse of the conductivity

    ie 1/sqrt( 1/R^2 +(wC-1/wL)^2) or ( 1/R^2 +(wC-1/wL)^2)^-(1/2)

  • Anonymous
    2 months ago

    The answer is B

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