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# The impedance of the parallel RLC circuit?

The impedance of the parallel RLC circuit shown is given by:

(The answer is B)Thanks

### 2 Answers

- ?Lv 72 months agoFavorite Answer
Consider the capacitor and the inductor. The impedance of the capacitor is 1/wC. The impedance of the inductor is in the reverse direction and is therefore -wL To add things in parallel we add their conductivities so the conductivity is wC - 1/wL

The conductivity of the resistor is 1/R but is 90 degrees different so that to get the resultant conductivity we must add using pythagoras' theory

conductivity = sqrt( 1/R^2 +(wC-1/wL)^2)

finally the magnitude of the impedance is the inverse of the conductivity

ie 1/sqrt( 1/R^2 +(wC-1/wL)^2) or ( 1/R^2 +(wC-1/wL)^2)^-(1/2)

- Anonymous2 months ago
The answer is B