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Can someone help me with this chemistry question?
Consider the reaction.
The concentrations of the products at equilibrium are [PCl3]=0.110 M and [Cl2]=0.230 M . What is the concentration of the reactant, PCl5 , at equilibrium?
- Roger the MoleLv 71 month ago
𝐾c = [PCl3] [Cl2] / [PCl5]
0.0420 = (0.110) (0.230) / [PCl5]
Solve for [PCl5] algebraically:
PCl5 = 0.602 M