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82.9 J of heat are applied to a 51.7 g sample of gold at 20.0 oC. What is the final temperature of the metal? ?
- az_lenderLv 72 months ago
Internet says heat capacity of gold at 25C is 0.129 J/g*C.
82.9 J = (0.129 J/g*C)*(51.7 g)*(delta-T) =>
delta-T = 12.4 degrees C.
Final temperature = 32.4 degrees C.