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82.9 J of heat are applied to a 51.7 g sample of gold at 20.0 oC. What is the final temperature of the metal? ?

1 Answer

  • 2 months ago

    Internet says heat capacity of gold at 25C is 0.129 J/g*C.

    82.9 J = (0.129 J/g*C)*(51.7 g)*(delta-T) =>

    delta-T = 12.4 degrees C.

    Final temperature = 32.4 degrees C.

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