Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. **There will be no changes to other Yahoo properties or services, or your Yahoo account.** You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

## Trending News

### 2 Answers

- az_lenderLv 72 months agoFavorite Answer
I see an unbalanced parenthesis after the "c" but I'm going to ignore it and suppose that the argument of the arcsin is (x/a + b). So the quantity (x/a + b) must be between -1 and +1, inclusive.

When x/a + b = -1, you have x/a = -b - 1, and x = -ab - a.

When x/a + b = +1, you have x/a = 1 - b, and x = a - ab.

The third choice in the list seems to be correct.

- PopeLv 72 months ago
You mean this?

f(x) = sin⁻¹(x/a + b) + c

a, b, c ∈ (-∞, 0)

The domain of the sin⁻¹ function is [-1, 1], and the added constant is of no consequence.

-1 ≤ x/a + b ≤ 1

-1 - b ≤ x/a ≤ 1 - b

-a - ab ≥ x ≥ a - ab ... (multiplication by a, a negative)

a - ab ≤ x ≤ -a - ab

a(1 - b) ≤ x ≤ -a(1 + b)

Domain: [a(1 - b), -a(1 + b)]

That is the second choice on the list.