Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

 Can anyone please help me solve this math problem?

A triangle has three vertices given by the points (1,p), (3,0) and (11,0) where p is a positive constant. The triangle is transformed using the matrix [ 6 −2 ]. Given that the transformed 1 2 triangle has an area of 364 square units, what is the value of p?

Attachment image

1 Answer

Relevance
  • 1 month ago
    Favorite Answer

    vertices of triangle 

    (1,p), (3,0) and (11,0) 

                         1    3            3      11         11   1

    area = (1/2) l          l   +    l            l   +   l         l

                        p     0            0       0          0      p

                = (1/2)[-3p + 0 +11P]

    Given: Area of triangle is 364 sq units

    Now, 364 = 4p

    p = 91

    I hope this helps!

Still have questions? Get your answers by asking now.