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# Can anyone please help me solve this math problem?

A triangle has three vertices given by the points (1,p), (3,0) and (11,0) where p is a positive constant. The triangle is transformed using the matrix [ 6 −2 ]. Given that the transformed 1 2 triangle has an area of 364 square units, what is the value of p?

### 1 Answer

- jacob sLv 71 month agoFavorite Answer
vertices of triangle

(1,p), (3,0) and (11,0)

1 3 3 11 11 1

area = (1/2) l l + l l + l l

p 0 0 0 0 p

= (1/2)[-3p + 0 +11P]

Given: Area of triangle is 364 sq units

Now, 364 = 4p

p = 91

I hope this helps!