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Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Chemistry problem?

What is the temperature change when 50.0Ml of 0.500M HCL is mixed with 75.0 Ml of 0.400 M NaOH. The standard enthalpy is -57.92 Kj/mol. 4.184JGC specific heat of water is used in this with a pressure calorimeter of 22C.

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  • 1 month ago
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    First, be careful with upper and lower case letters in chemistry. Conventions are important for communication. So, for example, I am guessing that the volume you mean is mL, hydrochloric acid is HCl, kilojoules is kJ, and the specific heat of water has units here of J/gC.

    moles HCl = 0.025 mol

    moles NaOH = 0.030 mol

    So, HCl is the limiting reactant. 

    Heat released by the reaction = 0.025 mol X -57.92 kJ/mol = -1.448 kJ = -1448 J

    Heat absorbed by the solution = +1448 J

    q = m c (T2-T1)

    1448 J = 125 g (4.184 J/gC) (T2-22 C)

    T2 = 24.8 C

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