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Anonymous asked in Science & MathematicsChemistry · 1 month ago

An iron calorimeter has a mass of 150 g. It holds 300 g of water. The temperature is 21.5​ degrees ​C.?

An iron calorimeter has a mass of 150 g. It holds 300 g of water. The temperature is 21.5​ degrees ​C. When a 100-g hot metal cylinder at 99.5​ degrees ​C is dropped into the calorimeter, the mixture reaches an equilibrium temperature of 31​ degrees C. Assuming heat exchange with the surroundings to be negligible, calculate the specific heat capacity of the metal cylinder.

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  • 1 month ago
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    Heat gained by calorimeter = [m c (T2-T1)]iron + [m c (T2-T1)]water

    q = (150 g)(0.444 J/gC)(31.0 - 21.5) + (300 g) (4.184 J/gC) (31-21.5) 

    q = 12557.1 J

    q lost by metal = -12557.1 J

    -12557.1 J = 100 g (c) (31-99.5C)

    c = 1.83 J/gC

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