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An iron calorimeter has a mass of 150 g. It holds 300 g of water. The temperature is 21.5 degrees C.?
An iron calorimeter has a mass of 150 g. It holds 300 g of water. The temperature is 21.5 degrees C. When a 100-g hot metal cylinder at 99.5 degrees C is dropped into the calorimeter, the mixture reaches an equilibrium temperature of 31 degrees C. Assuming heat exchange with the surroundings to be negligible, calculate the specific heat capacity of the metal cylinder.
- hcbiochemLv 71 month agoFavorite Answer
Heat gained by calorimeter = [m c (T2-T1)]iron + [m c (T2-T1)]water
q = (150 g)(0.444 J/gC)(31.0 - 21.5) + (300 g) (4.184 J/gC) (31-21.5)
q = 12557.1 J
q lost by metal = -12557.1 J
-12557.1 J = 100 g (c) (31-99.5C)
c = 1.83 J/gC