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# PHYSICS ASAP?!(11)?

When a mass of 25 g is attached to a certain

spring, it makes 16 complete vibrations in

4.5 s.

What is the spring constant of the spring?

Answer in units of N/m.

### 1 Answer

Relevance
• 16 rev / 4.5 s = 3.56 rev/s

f = (1/2π)√(k/M) = 3.56

(1/2π)√(k/0.025) = 3.56

√(k/0.025) = 22.34

k/0.025 = 499.1

k = 12.48 N/m

Springs and weight

k = F/d

k is spring constant in N/m

F is force and d is deflection

ω = √(k/M)

f = (1/2π)√(k/M)

T = 1/f = 2π√(M/k)

T is period in seconds

ω is angular frequency of bounce

f is frequency in Hz

ω = 2πf

M is mass in kg

PE = ½kd²

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