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Can someone help me with trig please?

Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ 𝜃 ≤ 2𝜋.

I'll attach the image

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2 Answers

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  • 1 month ago

    (a) r = sqrt(7^2 + (7sqrt(3))^2) = sqrt(49 + 49*3) = 14

     theta = arctan(-sqrt(3)) = 2pi - pi/3 = 5pi/3

    (look at the question -- you need RADIANS not degrees 5pi/3 = 300 degrees)

    (b) r = 8sqrt(2) and pi/4  (pi/4 = 45 degrees)

  • 1 month ago

    a)

    h = sqrt(7^2 + (-7sqrt(3))^2) = 14

    4th quad

    arcsin(-7sqrt(3)/14) = 5pi/3

    arccos(7/14) = 5pi/3

    b)

    h = sqrt(64 +64) = 8sqrt(2)

    1st quad

    arcsin(8/8sqrt(2)) = pi/4

    arccos(8/8sqrt(2)) = pi/4

    You were correct, but put degrees instead of rads

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