What is Kc?

Question

 I filled out the ICE chart which is the photo attached. Kc=[HI]^2/[H2][I2]

I used values from the E part of the chart. Should I be using different values or was it a calculation error? My answer was incorrect. 

I2 E was 0.0500 if you cannot read it. And 2HI E was 5.2 

Update:

EDIT: forgot to include: "The following reaction was performed in a sealed vessel at 724 ∘C " and "Initially, only H2 and I2 were present at concentrations of [H2]=3.05M and [I2]=2.65M . The equilibrium concentration of I2 is 0.0500 M . What is the equilibrium constant, Kc, for the reaction at this temperature?" if helpful. Thanks

Answer 1

You have set up the ICE table correctly. So if you calculated the answer as Bobby did in his answer, you should be good.

Answer 2

you definitely need to add the rest of the problem AND the value you calculated. 

Answer 3

H2(g)+I2(g)⇌2HI(g)

Kc = [HI]^2 / [H2] *[I2]

 = 5.2*^2 / 0.45 * 0.05

= 1200  . what is your answer ?

Answer 4

Go find, seek, show me, where is it, what's that, do ya wannabe dance