Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

jen asked in Science & MathematicsPhysics · 1 month ago

last physics problem need help!!?

A cube with an edge of 2.3 m is completely submerged in freshwater. The density of the cube is 4780 kg/m^3, and the density of freshwater is 1000 kg/m^3. 

Weight of the cube-

buoyant force the water exerts on the cube-

calculate the apparent weight of the cube when submerged in freshwater-

2 Answers

Relevance
  • 1 month ago

    volume is 2.3³ = 12.167 m³

    4780 kg/m³ x 12.167 m³ = 58200 kg

    weight is 58200 kg x 9.8 N/kg = 570000 N

    mass of same volume of water =

    1000 kg/m³ x 12.167 m³ = 12167 kg

    diff is buoyancy = 45991 kg or 450700 N

    apparent weight is 570000 – 450700 = 120000 N

  • John
    Lv 7
    1 month ago

    The buoyancy force is the weight of the displaced fluid (cube volume x water density x gravitational accleration), which is in the upwards direction. The weight of the cube itself is cube volume x cube density x gravitational acceleration, in the downwards direction. The difference is the apparent weight.

Still have questions? Get your answers by asking now.