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jen asked in Science & MathematicsPhysics · 1 month ago

last physics problem need help!!?

A cube with an edge of 2.3 m is completely submerged in freshwater. The density of the cube is 4780 kg/m^3, and the density of freshwater is 1000 kg/m^3. 

Weight of the cube-

buoyant force the water exerts on the cube-

calculate the apparent weight of the cube when submerged in freshwater-

2 Answers

  • 1 month ago

    volume is 2.3³ = 12.167 m³

    4780 kg/m³ x 12.167 m³ = 58200 kg

    weight is 58200 kg x 9.8 N/kg = 570000 N

    mass of same volume of water =

    1000 kg/m³ x 12.167 m³ = 12167 kg

    diff is buoyancy = 45991 kg or 450700 N

    apparent weight is 570000 – 450700 = 120000 N

  • John
    Lv 7
    1 month ago

    The buoyancy force is the weight of the displaced fluid (cube volume x water density x gravitational accleration), which is in the upwards direction. The weight of the cube itself is cube volume x cube density x gravitational acceleration, in the downwards direction. The difference is the apparent weight.

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