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The Cp of steam is 2.01 J/g°C. How much energy is needed to heat 52.0 grams of steam from 100.0°C to 120.0°C?
- Roger the MoleLv 72 months agoFavorite Answer
(2.01 J/g°C) x (52.0 g) x (120.0 - 100.0)°C = 2090 J