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The pH of a 0.150 M solution of a weak base is 10.98. Calculate the pH of a 0.04 M solution of the base.?
- BobbyLv 71 month ago
[OH-] = SQRT(Kb*c) / pOH = 14 - 10.98 = 3.02
10^-3.02 = SQRT (Kb *0.150)
9.55E-04 = Kb /0.150
Kb= 1.43 * 10 ^-4
in the second solution
[OH-] = SQRT( 1.43 * 10 ^-4 * 0.04)
pOH = 2.62
pH = 11.4 .... your answer