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Find the heat capacity of the bomb calorimeter.?
42.The combustion of toluene has a ΔErxn of −3.91 × 103kJ/mol. When 1.35 g of toluene (C7H8) undergoes combustion in a bomb calorimeter, the temperature rises from 23.46 ∘C to 37.91 ∘C. Find the heat capacity of the bomb calorimeter.
Express your answer using three significant figures.
- hcbiochemLv 72 months ago
Heat released by the combustion:
1.35 g / 92.14 g/mol X -3.91X10^3 kJ/mol = -57.29 kJ
So, the calorimeter absorbed +57.29 kJ of heat or 5.729X10^4 J
For the calorimeter,
q = C (T2-T1)
5.729X10^4 J = C(37.91-23.46 C)
C = 3.96X10^3 J/C