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Find the heat capacity of the bomb calorimeter.?

42.The combustion of toluene has a ΔErxn of −3.91 × 103kJ/mol. When 1.35 g of toluene (C7H8) undergoes combustion in a bomb calorimeter, the temperature rises from 23.46 ∘C to 37.91 ∘C. Find the heat capacity of the bomb calorimeter.

Express your answer using three significant figures.

1 Answer

  • 2 months ago

    Heat released by the combustion:

    1.35 g / 92.14 g/mol X -3.91X10^3 kJ/mol = -57.29 kJ

    So, the calorimeter absorbed +57.29 kJ of heat or 5.729X10^4 J

    For the calorimeter,

    q = C (T2-T1)

    5.729X10^4 J = C(37.91-23.46 C) 

    C = 3.96X10^3 J/C

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