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Uniform Fields - Physics?
If it takes 6.0 V to move a 6.2 uC charge from position A to position B, what work is done on the charge? What total energy is stored in the charge? If the charge has a mass of 0.015 kg and is released, what is the speed of the charge when it returns to point A?
- oldschoolLv 71 month agoFavorite Answer
Notice that volts = Joules/Coulomb = J/C so Work = qV = 6.2e-6*6 = 37.2µJ
At point A, all of its potential energy is converted to kinetic energy
37.2e-6 = ½*0.015*V²
V = 0.07m/s = 7cm/s