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Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Chemistry help?

A sample of lead at an temperature of 22.5 C absorbs 2.25 x 10^4 kJ of heat. The sample's temperature increases to 30.5 C. Calculate the mass in grams of lead on the sample. The specific heat constant of lead is 0.128 J/g-C

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  • 1 month ago

    (2.25 x 10^4 x 10^3 J) / (0.128 J/g·°C) / (30.5 - 22.5)°C = 21972656.2 g =

    22.0 x 10^7 g Pb

  • 1 month ago

    22500 J = 0.128 J/g•C x M g x (30.5–22.5)ºC

    M = 22000 g or 22 kg

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