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Can anyone help me out with this chemistry problem?

54.0 mL of 3.70 M sodium hydroxide is combined with 44.0 mL of 1.30 M magnesium chloride. What mass in grams of solid forms?

1 Answer

  • 2 months ago

    Balanced equation: MgCl2(aq) + 2 NaOH(aq) --> Mg(OH)2(s) + 2 NaCl(aq)

    There are several ways to determine the limiting reactant. When you are asked for the mass of the product formed, the easiest approach is to use each reactant independently to calculate the mass of product formed.

    0.0540 L X 3.70 mol/L NaOH X(1 mol Mg(OH)2/2 mol NaOH) X 58.32 g/mol Mg(OH)2 = 5.83 g Mg(OH)2

    0.0440 L X 1.30 mol/L MgCl2 X (1 mol Mg(OH)2/1 mol MgCl2) X 58.32 g/mol Mg(OH)2 = 3.34 g Mg(OH)2

    Because the mass of product is smaller using the amount of MgCl2, that is the limiting reactant, and the expected yield is 3.34 g Mg(OH)2.

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