Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Suppose a piece of dust finds itself on a CD. If the spin rate of the CD is 470 rpm, and the piece of dust is 4.5 cm from the center, ?

what is the total distance (in m) traveled by the dust in 8 minutes? (Ignore accelerations due to getting the CD rotating.) 

____m

3 Answers

Relevance
  • oubaas
    Lv 7
    2 months ago
    Favorite Answer

    angular speed ω = 2PI/60*n = 0.10472*470 = 49.22 rad/sec 

    tangential speed Vt = ω*r = 49.22*0.045 = 2.21 m/sec 

    distance d = Vt*t = 2.21*8*60 = 1063 m (1100 with just 2 sign. digits)

  • Ash
    Lv 7
    2 months ago

    travel distance = rpm * (time in min) * circumference that dust makes)

    = (470 rpm)* (8 min) * (2𝜋r)

    = (470 rpm)* (8 min) * (2𝜋*0.045 m)

    = 1063 m

  • Anonymous
    2 months ago

    are these seriously questions you are getting in your homework? These are stupid, why don't they ask questions relevant to something you might actually care about?

Still have questions? Get your answers by asking now.