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Anonymous asked in Science & MathematicsPhysics · 2 months ago

Suppose a piece of dust finds itself on a CD. If the spin rate of the CD is 470 rpm, and the piece of dust is 4.5 cm from the center, ?

what is the total distance (in m) traveled by the dust in 8 minutes? (Ignore accelerations due to getting the CD rotating.) 


3 Answers

  • oubaas
    Lv 7
    2 months ago
    Favorite Answer

    angular speed ω = 2PI/60*n = 0.10472*470 = 49.22 rad/sec 

    tangential speed Vt = ω*r = 49.22*0.045 = 2.21 m/sec 

    distance d = Vt*t = 2.21*8*60 = 1063 m (1100 with just 2 sign. digits)

  • Ash
    Lv 7
    2 months ago

    travel distance = rpm * (time in min) * circumference that dust makes)

    = (470 rpm)* (8 min) * (2𝜋r)

    = (470 rpm)* (8 min) * (2𝜋*0.045 m)

    = 1063 m

  • Anonymous
    2 months ago

    are these seriously questions you are getting in your homework? These are stupid, why don't they ask questions relevant to something you might actually care about?

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