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If sin^2x = a and cos^2x=b, then for x in the first quadrant, sin2x+cos2x=?
- rotchmLv 72 months ago
Hint: Adapting to my notation, s2 + c2 = 2sc + c² - s² = 2√(ab) + b - a ...
And also, recall here that a+b = 1 ... can you simplify all that further?
You can rewrite it all solely with either the variable "a" or "b". Your choice!
- nyphdinmdLv 72 months ago
So sin(x) = sqrt(a) and cos(x) = sqrt(b)
cos(2x) = cos^2(x) - sin^2(x) = b - a
sin(2x) = 2sin(x)cos(x) = 2*sqrt(a*b) so
sin(2x) + cos(2x) = 2*sqrt(a*b) + b - a