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A 100kg cart with a 40 kg load on it is rolling on a flat, frictionless surface at 20 m/second. What is the velocity after the 40kg is...?
What is the velocity after the 40 kg load is dropped off?
What does "dropped off" mean in this scenario?
- NCSLv 72 months ago
What does "dropped off" mean is the key question.
"Dropped off" might mean jettisoned straight off the side. In that case, the forward momentum of each item is still 20 m/s (by conservation of forward momentum).
But "dropped off" might mean jettisoned off the back so that it has zero velocity. In that case conservation of momentum yields
140kg * 20m/s = 100kg * V + 40kg * 0m/s
final cart velocity V = 28 m/s
Personally, I'd go with the second meaning.
Hope this helps!
- ?Lv 72 months ago
It just remains the same ; total momentum is conserved : the cart will continue moving @ 20 m/sec and the same applies to the load till it lands !!!