Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Spade asked in Science & MathematicsPhysics · 2 months ago

A 100kg cart with a 40 kg load on it is rolling on a flat, frictionless surface at 20 m/second. What is the velocity after the 40kg is...?

What is the velocity after the 40 kg load is dropped off?

What does "dropped off" mean in this scenario?

2 Answers

Relevance
  • NCS
    Lv 7
    2 months ago

    What does "dropped off" mean is the key question.

    "Dropped off" might mean jettisoned straight off the side. In that case, the forward momentum of each item is still 20 m/s (by conservation of forward momentum).

    But "dropped off" might mean jettisoned off the back so that it has zero velocity. In that case conservation of momentum yields

    140kg * 20m/s = 100kg * V + 40kg * 0m/s

    final cart velocity V = 28 m/s

    Personally, I'd go with the second meaning.

    Hope this helps!

  • ?
    Lv 7
    2 months ago

    It just remains the same ; total momentum is conserved : the cart will continue moving @ 20 m/sec  and the same applies to the load till it lands !!!

Still have questions? Get your answers by asking now.