Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Anonymous asked in Science & MathematicsChemistry · 2 months ago

Chem questions?

1.Normal saline solution contains 0.90 g of sodium chloride per 100. mL of solution. What is the molar concentration (M) of sodium chloride in normal saline? 

2.How would you prepare 250. mL of 0.300 M LiNO3 solution, starting from the solid solute? Do a calculation AND write one sentence describing how you would prepare the solution.

2 Answers

  • 2 months ago
    Favorite Answer


    (0.90 g NaCl) / (58.4430 g NaCl/mol) / (0.100 L) = 0.154 mol/L = 0.154 M NaCl


    (0.250 L) x (0.300 mol LiNO3/L) x (68.9459 g LiNO3/mol) = 5.17 g LiNO3

    Supposing the solution to be made is aqueous:

    Weigh out 5.17 grams of lithium nitrate, put it in a 250-mL volumetric flask, add enough water to dissolve the salt with swirling, add more water until the solution reaches the flask's mark, and mix thoroughly.  

  • 2 months ago


    .90 g  x. 1mol/ 58.44 g = .015 mol NaCl

    .015 mol /.1L = .15M


    250 ml = 0.25 L of 0.300 M LiNO3

                   0.25 L x (.300 mol/L) = .075 moles  LiNO3

    Amount of solid  LiNO3 required in grams 

    0.075 moles  LiNO3 x 68.946 g/mol LiNO3 = 5.17 g LiNO3 

    Please  Rate my work!!

Still have questions? Get your answers by asking now.