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Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Physics Spring Scenario Question?

A compression spring is mounted horizontally as shown to the right. A crate, which has a mass of 8.5 kilograms, is placed against the spring with a force of 350 N. As a result the spring is compressed a distance of 50 cm. The force is then taken away so the spring uncompresses and pushes the crate along a horizontal, frictionless surface.

1) What is the spring constant k of this spring?

2) With the spring compressed at 50 cm:

a) How much elastic potential energy Us will be stored in the spring?

b) How much work W was done in compressing the spring?

c) What will be the velocity v of the crate after it has left the spring?

3) With the spring compressed at 100 cm:

a) How much force F would it take to compress the spring?

b) How much elastic potential energy Us will be stored in the spring?

c) How much work W was done in compressing the spring?

d) What will be the velocity v of the crate after it has left the spring?

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2 Answers

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  • oubaas
    Lv 7
    2 months ago
    Favorite Answer

    1) What is the spring constant k of this spring?

    k = F/x = 350/0.5 = 700 N/m

    2) With the spring compressed at 50 cm:

    a) How much elastic potential energy Us will be stored in the spring?

    Us = k/2*x^2 = 700/(2)*0.5^2 = 87.5 joule

    b) How much work W was done in compressing the spring?

    W = Us = 87.5 joule

    c) What will be the velocity v of the crate after it has left the spring?

    kx^2 = mV^2V = √ k*x^2/m = √ 700*0.25/8.5 = 4.54 m/sec

    3) With the spring compressed at 100 cm:

    a) How much force F' would it take to compress the spring?

    F' = k*x' = 700*1 = 700 N

    b) How much elastic potential energy U's will be stored in the spring?

    U's = k^2*x'^2 = 350*1 = 350 joule

    c) How much work W' was done in compressing the spring?

    W' = U's = 350 joule

    d) What will be the velocity v' of the crate after it has left the spring?

    V' = √ k*x'^2/m = √ 700*1/8.5 = 9.08 m/sec

  • Jim
    Lv 7
    2 months ago

    U = 1/2 kx², insert numbers and solve for k

    PE = KE

    KE = 1/2 mv²

    F = ma

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