I need 0.200 mol each of zinc metal and copper (ll) nitrate for an experiment. What is the mass of copper (ll) nitrate ?

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  • 1 month ago

    (0.200 mol Cu(NO3)2) x (187.5558 g Cu(NO3)2/mol) = 37.5 g Cu(NO3)2

  • david
    Lv 7
    1 month ago

    Erica ---  find the molar mass of Copper(II) nitrate  then multiply by 0.200

     == Find the atomic mass of zinc  then multiply by 0.200

    This is the easy part of chemistry.

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