Anonymous
Anonymous asked in Science & MathematicsMathematics · 3 months ago

A letter of the alphabet is selected at random . Find the probability that the letter is a :

a) vowel ( exclude y )

b) consonant (include y)

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• ?
Lv 7
3 months ago

The vowels are A,E,I,O and U.  That means you have a probability of 5/26 of selecting a vowel at random, because there are 26 letters in the alphabet.

That means there is a 21/26 probability of selecting a consonant.

Think of probability in relation to a coin.  A coin has one side head and one side tails.  There are only two choices, so the chance of flipping the coin and it landing on heads is 1/2.  1 head out of two choices.  In the alphabet, there are 26 letters you can draw.  There is only 1 letter A, so the probability of selecting A when all the letters are put in a bucket is 1 in 26, or 1/26.   Five of the letters are vowels, so there is a 5/26 chance of drawing a vowel.

• 3 months ago

Seriously?

a) 5 vowels, 26 letters, probability ≈ 19.23%

b) consonant = not vowel = 1 - 19.23% = 80.77%

• david
Lv 7
3 months ago

a.   5/26

b.  21/26