What is the molarity of the acid?

Question

An sample of HC1 of unknown concentration is brought to you for analysis. You titrate 10.00 ml of the acid to its endpoint with 23.56 ml of 0.100 M NaOH.  How did you get to your answer? Ty! 

Answer 1

balanced rxn

.. 1 HC1 + 1 NaOH ---> 1 NaCl + 1 H2O

then

.. 23.56 mL NaOH.... 0.100 mmol NaOH..  1 mmol HCl

 ----- ---- ---- ---- ---- x ---- ---- --- ---- --- --- x ----- ------ ----- = 0.236 M HCl

.. 10.00mL HCl .. ... .... . .1 mL NaOH.. .. . 1 mmol NaOH

Answer 2

HCl + NaOH → NaCl + H2O  [balanced as written]

(23.56 mL x 0.100 M NaOH) x (1 mol HCl / 1 mol NaOH) / (10.00 mL HCl) =

0.2356 M HCl