Calculate the pH of a solution obtained by mixing equal volumes of a strong acid solution of pH? 3.00 and a strong base solution of pH 12.00?

Answer 1

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pH = 3.00 

[H+] = 1*10^-3 

pH = 12.0

pOH =  2.0

[OH-] =1*10 ^-2 

when these 2 react we have

moles of OH- =  1*10^-2  -  1* 10 ^-3  = 9.00*10^-3 in volume *2 

[OH-] = 9.00*10^-3 /2 = 4.50*10 ^-3

pOH = 2.35

pH = 11.65